By William G. Hoover
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Benjamin Bederson contributed to the realm of physics in lots of components: in atomic physics, the place he completed renown through his scattering and polarizability experiments, because the Editor-in-Chief for the yank actual Society, the place he observed the creation of digital publishing and a outstanding progress of the APS journals, with ever expanding world-wide contributions to those hugely esteemed journals, and because the originator of a few overseas physics meetings within the fields of atomic and collision physics, that are carrying on with to at the present time.
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Additional resources for Molecular Dynamics (Lecture Notes in Physics)
The function solve returns a list of solutions. Its first argument is an equation (or a list of equations), and the second one is an unknown variable (or a list of unknown variables). If the right-hand side of an equation is zero, then it may be omitted together with =. The second argument may be omitted, if the unknown variables are the only variables contained in the equations. Every solution in the list returned by solve is the equality with the unknown variable in the left-hand side, or the list of such equalities in the case of an equation system.
Operator f; x:=xx$ y:=yy$ let f(x)=y; clear x; f(x); f(xx); clear y; f(xx); clear f(xx); yy y x:=xx$ y:=yy$ f(x):=y; f(xx) := yy clear x; f(x); f(xx); clear y; f(xx); clear f(xx); yy yy The statements l e t x= ... and x: = ... both change the value of x (the first one, to the unevaluated right-hand side, while the second one, to its value). Therefore, naturally, any of these statements destroys the result of a previous one. At each moment, only one substitution for a variable x raised to an integer power can exist.
By the way, you can see that an assignment has a value, and may be used in an expression. % Taylor series for exp procedure expl(x,n); begin scalar s,u; s:=l; u:=l; for i:=l:n do « u:=u*x/i; s:=s+u » ; return s end$ on div,revpri; expl(x,10); clear expl; ! ^ 1 l 2 l 3 1 4 2 6 x9 + + x + 24 120 1 fi 720 1 « 7 5040 40320 x10 3628800 362880 3628800 °/0 method using small variables procedure exp2(x); begin scalar s,u,i; s:=l; u:=x; i:=l; repeat « s:=s+u; i:=i+l; u:=u*x/i » until u=0; return s end$ weight x=l$ wtlevel 10$ exp2(x); exp2(x+x~2); clear exp2; .