By Robert L.Boylestead, Louis Nashelsky
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Extra info for Instructors solution manual to electronic devices and circuit theory
Example text
However, the voltage-divider configuration continues to have the least sensitivities to change in β. 40 25. 31 V 26. 09 μ A 27. (a) IB = 28. 07 V 41 29. 72 V 30. 95 V 31. 04 μ A (d) VCE = VC = 8 V 42 32. 6 kΩ, RB = 430 kΩ 33. I Csat = 34. 7 V = 2 ⎬ 2 unknowns! 5 kΩ, R1 = 43 kΩ 35. 65 mA ≅ I 2 kΩ 36. I2 kΩ = 37. 4 kΩ) = I = 2 mA 38. 8 kΩ 39. VB ≅ 40. IE = 41. 76 V 42. 62 kΩ 45 43. (a) From Fig. 12:1 44. (a) Open-circuit in the base circuit Bad connection of emitter terminal Damaged transistor (b) Shorted base-emitter junction Open at collector terminal (c) Open-circuit in base circuit Open transistor 45.
51 Chapter 5 1. (a) If the dc power supply is set to zero volts, the amplification will be zero. (b) Too low a dc level will result in a clipped output waveform. 4 mW 2. − 3. xC = 4. − 5. 49 mA = 10 μA 52 6. 97 V (e) Av = (f) 7. 2 kΩ 40 kΩ 13 Ω 53 8. 84 25 μ A Ii (d) IL = (e) Av = 9. 88 54 10. 11. 3 kΩ (c) Av = − (d) Av = − 12. 79 Ω (a) Test βRE ≥ 10R2 ? 28 (vs. 6) 13. 56 Ω ? 68 V 14. Test βRE ≥ 10R2 ? 88 15. 11 16. Even though the condition ro ≥ 10RC is not met it is sufficiently close to permit the use of the approximate approach.
62 kΩ 45 43. (a) From Fig. 12:1 44. (a) Open-circuit in the base circuit Bad connection of emitter terminal Damaged transistor (b) Shorted base-emitter junction Open at collector terminal (c) Open-circuit in base circuit Open transistor 45. 4 V reveals that the 18 kΩ resistor is not making contact with the base terminal of the transistor. 64 V vs. 64 V With IB = 0 μA, VB = 18 kΩ + 91 kΩ ∴ Assume base circuit “open” The 4 V at the emitter is the voltage that would exist if the transistor were shorted collector to emitter.